Update after version 14.0.0.0, the bitrate of the video is incorrect

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eldenlord
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Joined: 06 Jun 2022, 10:32

06 Jun 2022, 10:37

Update after version 14.0.0.0, the bitrate of the video is incorrect. For example, JAV is usually 5744+256 (video+audio), and now version 18.0.0.0 shows 5737+255 (video+audio). I hope it can display data like Mediainfo.
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admin
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06 Jun 2022, 12:01

Can I have an example in Private Messages?
eldenlord
Posts: 5
Joined: 06 Jun 2022, 10:32

06 Jun 2022, 12:41

admin wrote:
06 Jun 2022, 12:01
Can I have an example in Private Messages?
ok, look PM
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admin
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06 Jun 2022, 13:55

The Audio bitrate is 255.999, I will round it to 256 instead of using 255.
The Video bitrate is 5670755, so it should be 5671 from my point of view.
eldenlord
Posts: 5
Joined: 06 Jun 2022, 10:32

06 Jun 2022, 15:02

admin wrote:
06 Jun 2022, 13:55
The Audio bitrate is 255.999, I will round it to 256 instead of using 255.
The Video bitrate is 5670755, so it should be 5671 from my point of view.
I usually process videos from DMM.com, and the coding mode of DMM is about 6000 bitrate average. In the previous WMV era, 5744+256=6000kbps was a standard, so we can judge whether the video source is correct or not. Many of my friends and I think that Windows attributes are absolutely not as accurate as the metadata of MediaInfo and Potplayer, so I think it would be better to quote the Text of MediaInfo.
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admin
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06 Jun 2022, 16:55

Your point is clear.

We are dealing with the Variable bitrate. So it changes in different parts of video.
On the other hand, we need a single number to display.

I am just trying to understand which value is more correct to use.
Your file indeed contains:
bitrate=5744
vbv_maxrate=5744

I can try to find a way to extract that data from the file.
The question is - is it reliable for other videos?

The video length is 312,18 sec.
In your case we can try to calculate the overall size of the file like that:
(5 740 000 + 256 000) * 312,18 / 8 = 233 978 910 bytes.
It is larger than 231 533 364. The difference is 2 445 546 bytes (~2.35 MB).

In my case:
(5 670 755 + 256 000) * 312,18 / 8 = 231 276 796 bytes.
It is less than 231 533 364. The difference is 256 567 bytes (~0.24 MB).
So my estimation is ten times closer to the real file size.

So I would say in your case 5744 is the max bitrate, not average.
What do you think?
eldenlord
Posts: 5
Joined: 06 Jun 2022, 10:32

06 Jun 2022, 17:50

admin wrote:
06 Jun 2022, 16:55
Your point is clear.

We are dealing with the Variable bitrate. So it changes in different parts of video.
On the other hand, we need a single number to display.

I am just trying to understand which value is more correct to use.
Your file indeed contains:
bitrate=5744
vbv_maxrate=5744

I can try to find a way to extract that data from the file.
The question is - is it reliable for other videos?

The video length is 312,18 sec.
In your case we can try to calculate the overall size of the file like that:
(5 740 000 + 256 000) * 312,18 / 8 = 233 978 910 bytes.
It is larger than 231 533 364. The difference is 2 445 546 bytes (~2.35 MB).

In my case:
(5 670 755 + 256 000) * 312,18 / 8 = 231 276 796 bytes.
It is less than 231 533 364. The difference is 256 567 bytes (~0.24 MB).
So my estimation is ten times closer to the real file size.

So I would say in your case 5744 is the max bitrate, not average.
What do you think?
Maybe I don't know the real coding mode of DMM, but you can try to add options: calculate the average, or follow the bitrate like Mediainfo. I usually download DMM videos, and sometimes when the network fluctuates, the finished .mp4 can't find the 5744 bitrate data anyway, which can prove that .mp4 is absolutely broken.
eldenlord
Posts: 5
Joined: 06 Jun 2022, 10:32

06 Jun 2022, 18:10

I'll send you a complete video for your test. Look PM
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admin
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12 Jul 2022, 20:13

Audio bitrate should be more accurate in VTM 19.0.0.0.
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